Explanation of Linear Search in Java Integer and String
public class LinearSearch {
public static void main(String[] args) {
/*int arr[]={5,6,7,8,9,2,10};
int number=10; // for integer value
int temp=0;
for (int i=0;i<arr.length;i++){
if (arr[i]==number){
System.out.println("Number present at "+i+" position");
temp=temp+1;
}
}
if (temp==0){
System.out.println("number not present in array");
}
Output :
_________________________________________
Linear Search for String
String str[]={"sagar","kumar","ravi","sonu","monu"};
String name ="ravi";
int temp=0;
for (int i=0;i<str.length;i++){
if (str[i].equals(name)){
System.out.println("Name is present at "+i+ " position");
temp=temp+1;
}
}
if (temp==0){
System.out.println("not available");
}
}
}
Output :
public class LinearSearch {
public static void main(String[] args) {
/*int arr[]={5,6,7,8,9,2,10};
int number=10; // for integer value
int temp=0;
for (int i=0;i<arr.length;i++){
if (arr[i]==number){
System.out.println("Number present at "+i+" position");
temp=temp+1;
}
}
if (temp==0){
System.out.println("number not present in array");
}
Output :
_________________________________________
Linear Search for String
String str[]={"sagar","kumar","ravi","sonu","monu"};
String name ="ravi";
int temp=0;
for (int i=0;i<str.length;i++){
if (str[i].equals(name)){
System.out.println("Name is present at "+i+ " position");
temp=temp+1;
}
}
if (temp==0){
System.out.println("not available");
}
}
}
Output :
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Hello, my name is ravi kumar sagar. I'm a photographer and developer. i play with coding and learn with fun
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